Benutzer:Wikistefan87/Formeltest

${\frac {N_{\mathrm {\alpha } }}{N_{\mathrm {\beta } }}}=\mathrm {e} ^{-\Delta E \over kT}=\mathrm {e} ^{-(E_{1}-E_{2}) \over kT}$

$k={\frac {R}{N_{L}}}={\frac {8{,}314J\cdot mol}{6{,}023\cdot 10^{23}mol\cdot K}}=1{,}38\cdot 10^{-23}{\frac {J}{K}}$

${\frac {N_{\mathrm {\alpha } }}{N_{\mathrm {\beta } }}}$

${\delta }={\frac {v_{Probe}-v_{TMS}}{v_{TMS}}}\cdot 10^{6}ppm$

$v={\frac {{\gamma }B_{0}}{2{\pi }}}$

${\Delta }E=h\cdot v$

${\frac {g}{mol}}$

${\frac {g}{cm^{3}}}$

$p_{ges}<p_{a}+p_{b}\cdot$

$R_{f}={\frac {x_{Substanz}}{x_{FM}}}$

${C_{X}H_{Y}O_{Z}\rightarrow a\ CO+b\ H_{2}O}$

${CO+H_{2}O\rightarrow CO_{2}+H_{2}}$

${C+2\ H_{2}O\rightarrow 2\ H_{2}+CO_{2}}$

${2\ CH_{4}+O_{2}\rightarrow 2\ CO+2\ H_{2}}$

${\frac {1}{f}}={\frac {1}{g}}+{\frac {1}{b}}$

$f={\frac {1}{{\frac {1}{g}}+{\frac {1}{b}}}}$

$f={\frac {gb}{g+b}}$

$f={\frac {a^{2}-v^{2}}{4a}}$

$a=g+b\,$

$f(g+b)=gb=af\,$

$0=g+b-a\,$

$0=g^{2}+gb-ga\,$

$0=g^{2}-ga+af\,$

$g_{1,2}={\frac {a}{2}}\pm {\sqrt {{\frac {a^{2}}{4}}+af}}$

$v=g_{1}-g_{2}\,$

$v=2{\sqrt {{\frac {a^{2}}{4}}+af}}$

${\frac {v^{2}}{4}}={\frac {a^{2}}{4}}-af$

$af={\frac {a^{2}-v^{2}}{4}}$