Diskussion:Quecksilber(I)-iodid

If you can read this

Iodine is not a strong enough oxidizing agent to oxidize mercury. Delete this if there is anything wrong with what I say. --Chemicalinterest 22:06, 31. Aug. 2010 (CEST)

Iodine is strong enough oxidizing, the electrochemical potentials cannot be taken in account here, because the reaction does not occur in solution ;) Iodine, though generally less reactive than bromine, combines directly with many elements, for example silver, gold and aluminium, forming iodides. Mercury is also attacked and mercury(I) iodide, Hg2I2, is first formed but in the presence of excess iodine this is oxidised to mercury(II) iodide, HgI2. C. Chambers, A. K. Holliday, Modern inorganic chemistry, Butterworth & Co (Publishers) Ltd 1975, page 322. Best regards --NobbiNobb 14:32, 1. Sep. 2010 (CEST)

This may work in aquous solution as well because Hg₂I₂ is a (mainly) covalent compound. Concentrations of the products are very low and will push the redox potential in a way that allows the reaction. Would you expect gold to be oxidized by iodine? If not, you are wrong... --FK1954 15:06, 3. Sep. 2010 (CEST)